1
JEE Main 2021 (Online) 27th July Morning Shift
+4
-1
Out of Syllabus
The value of $$\mathop {\lim }\limits_{n \to \infty } {1 \over n}\sum\limits_{j = 1}^n {{{(2j - 1) + 8n} \over {(2j - 1) + 4n}}}$$ is equal to :
A
$$5 + {\log _e}\left( {{3 \over 2}} \right)$$
B
$$2 - {\log _e}\left( {{2 \over 3}} \right)$$
C
$$3 + 2{\log _e}\left( {{2 \over 3}} \right)$$
D
$$1 + 2{\log _e}\left( {{3 \over 2}} \right)$$
2
JEE Main 2021 (Online) 27th July Morning Shift
+4
-1
The value of the definite integral

$$\int\limits_{ - {\pi \over 4}}^{{\pi \over 4}} {{{dx} \over {(1 + {e^{x\cos x}})({{\sin }^4}x + {{\cos }^4}x)}}}$$ is equal to :
A
$$- {\pi \over 2}$$
B
$${\pi \over {2\sqrt 2 }}$$
C
$$- {\pi \over 4}$$
D
$${\pi \over {\sqrt 2 }}$$
3
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
If $$f(x) = \left\{ {\matrix{ {\int\limits_0^x {\left( {5 + \left| {1 - t} \right|} \right)dt,} } & {x > 2} \cr {5x + 1,} & {x \le 2} \cr } } \right.$$, then
A
f(x) is not continuous at x = 2
B
f(x) is everywhere differentiable
C
f(x) is continuous but not differentiable at x = 2
D
f(x) is not differentiable at x = 1
4
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
The value of the

integral $$\int\limits_{ - 1}^1 {\log \left( {x + \sqrt {{x^2} + 1} } \right)dx}$$ is :
A
2
B
0
C
$$-$$1
D
1
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