1
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
$$\mathop {\lim }\limits_{n \to \infty } \left( {{{{{(n + 1)}^{1/3}}} \over {{n^{4/3}}}} + {{{{(n + 2)}^{1/3}}} \over {{n^{4/3}}}} + ....... + {{{{(2n)}^{1/3}}} \over {{n^{4/3}}}}} \right)$$
is equal to :
A
$${4 \over 3}{\left( 2 \right)^{3/4}}$$
B
$${3 \over 4}{\left( 2 \right)^{4/3}} - {3 \over 4}$$
C
$${4 \over 3}{\left( 2 \right)^{4/3}}$$
D
$${3 \over 4}{\left( 2 \right)^{4/3}} - {4 \over 3}$$
2
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of the integral $$\int\limits_0^1 {x{{\cot }^{ - 1}}(1 - {x^2} + {x^4})dx} $$ is :-
A
$${\pi \over 2} - {1 \over 2}{\log _e}2$$
B
$${\pi \over 4} - {\log _e}2$$
C
$${\pi \over 4} - {1 \over 2}{\log _e}2$$
D
$${\pi \over 2} - {\log _e}2$$
3
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If f : R $$ \to $$ R is a differentiable function and f(2) = 6,
then $$\mathop {\lim }\limits_{x \to 2} {{\int\limits_6^{f\left( x \right)} {2tdt} } \over {\left( {x - 2} \right)}}$$ is :-
A
2f'(2)
B
24f'(2)
C
0
D
12f'(2)
4
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of $$\int\limits_0^{\pi /2} {{{{{\sin }^3}x} \over {\sin x + \cos x}}dx} $$ is
A
$${{\pi - 2} \over 8}$$
B
$${{\pi - 2} \over 4}$$
C
$${{\pi - 1} \over 2}$$
D
$${{\pi - 1} \over 4}$$
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