JEE Main 2025 (Online) 7th April Morning Shift | Statistics Question 1 | Mathematics

The mean and standard deviation of 100 observations are 40 and 5.1 , respectively. By mistake one observation is taken as 50 instead of 40 . If the correct mean and the correct standard deviation are $\mu$ and $\sigma$ respectively, then $10(\mu+\sigma)$ is equal to

447

445

449

451

JEE Main 2025 (Online) 4th April Evening Shift

MCQ (Single Correct Answer)

-1

Let the mean and the standard deviation of the observation $2,3,3,4,5,7, a, b$ be 4 and $\sqrt{2}$ respectively. Then the mean deviation about the mode of these observations is :

$\frac{1}{2}$

$\frac{3}{4}$

JEE Main 2025 (Online) 3rd April Evening Shift

MCQ (Single Correct Answer)

-1

Let the Mean and Variance of five observations $x_1=1, x_2=3, x_3=a, x_4=7$ and $x_5=\mathrm{b}, a>\mathrm{b}$, be 5 and 10 respectively. Then the Variance of the observations $n+x_n, n=1,2, \ldots, 5$ is

16.4

17.4

JEE Main 2025 (Online) 2nd April Evening Shift

MCQ (Single Correct Answer)

-1

If the mean and the variance of $6,4, a, 8, b, 12,10,13$ are 9 and 9.25 respectively, then $a+b+a b$ is equal to :

103

106

100

105

Questions Asked from Statistics (MCQ (Single Correct Answer))

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