1
JEE Main 2024 (Online) 9th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area (in square units) of the region enclosed by the ellipse $$x^2+3 y^2=18$$ in the first quadrant below the line $$y=x$$ is

A
$$\sqrt{3} \pi+1$$
B
$$\sqrt{3} \pi$$
C
$$\sqrt{3} \pi-\frac{3}{4}$$
D
$$\sqrt{3} \pi+\frac{3}{4}$$
2
JEE Main 2024 (Online) 9th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The parabola $$y^2=4 x$$ divides the area of the circle $$x^2+y^2=5$$ in two parts. The area of the smaller part is equal to :

A
$$\frac{2}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$$
B
$$\frac{2}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$$
C
$$\frac{1}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$$
D
$$\frac{1}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$$
3
JEE Main 2024 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area of the region in the first quadrant inside the circle $$x^2+y^2=8$$ and outside the parabola $$y^2=2 x$$ is equal to :

A
$$\frac{\pi}{2}-\frac{1}{3}$$
B
$$\pi-\frac{1}{3}$$
C
$$\pi-\frac{2}{3}$$
D
$$\frac{\pi}{2}-\frac{2}{3}$$
4
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If the area of the region $$\left\{(x, y): \frac{\mathrm{a}}{x^2} \leq y \leq \frac{1}{x}, 1 \leq x \leq 2,0<\mathrm{a}<1\right\}$$ is $$\left(\log _{\mathrm{e}} 2\right)-\frac{1}{7}$$ then the value of $$7 \mathrm{a}-3$$ is equal to :

A
1
B
0
C
2
D
$$-$$1
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