1
JEE Main 2019 (Online) 10th January Morning Slot
+4
-1
Let  $${\rm I} = \int\limits_a^b {\left( {{x^4} - 2{x^2}} \right)} dx.$$  If I is minimum then the ordered pair (a, b) is -
A
$$\left( {\sqrt 2 , - \sqrt 2 } \right)$$
B
$$\left( {0,\sqrt 2 } \right)$$
C
$$\left( { - \sqrt 2 ,\sqrt 2 } \right)$$
D
$$\left( { - \sqrt 2 ,0} \right)$$
2
JEE Main 2019 (Online) 10th January Morning Slot
+4
-1
If the area enclosed between the curves y = kx2 and x = ky2, (k > 0), is 1 square unit. Then k is -
A
$$\sqrt 3$$
B
$${{\sqrt 3 } \over 2}$$
C
$${2 \over {\sqrt 3 }}$$
D
$${1 \over {\sqrt 3 }}$$
3
JEE Main 2019 (Online) 9th January Evening Slot
+4
-1
The area of the region

A = {(x, y) : 0 $$\le$$ y $$\le$$x |x| + 1  and  $$-$$1 $$\le$$ x $$\le$$1} in sq. units, is :
A
$${2 \over 3}$$
B
2
C
$${4 \over 3}$$
D
$${1 \over 3}$$
4
JEE Main 2019 (Online) 9th January Evening Slot
+4
-1
If   $$\int\limits_0^{{\pi \over 3}} {{{\tan \theta } \over {\sqrt {2k\,\sec \theta } }}} \,d\theta = 1 - {1 \over {\sqrt 2 }},\left( {k > 0} \right),$$ then value of k is :
A
4
B
$${1 \over 2}$$
C
1
D
2
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