1
JEE Main 2022 (Online) 28th June Evening Shift
+4
-1 Let f : R $$\to$$ R be a differentiable function such that $$f\left( {{\pi \over 4}} \right) = \sqrt 2 ,\,f\left( {{\pi \over 2}} \right) = 0$$ and $$f'\left( {{\pi \over 2}} \right) = 1$$ and

let $$g(x) = \int_x^{\pi /4} {(f'(t)\sec t + \tan t\sec t\,f(t))\,dt}$$ for $$x \in \left[ {{\pi \over 4},{\pi \over 2}} \right)$$. Then $$\mathop {\lim }\limits_{x \to {{\left( {{\pi \over 2}} \right)}^ - }} g(x)$$ is equal to :

A
2
B
3
C
4
D
$$-$$3
2
JEE Main 2022 (Online) 28th June Evening Shift
+4
-1 Let f : R $$\to$$ R be a continuous function satisfying f(x) + f(x + k) = n, for all x $$\in$$ R where k > 0 and n is a positive integer. If $${I_1} = \int\limits_0^{4nk} {f(x)dx}$$ and $${I_2} = \int\limits_{ - k}^{3k} {f(x)dx}$$, then :

A
$${I_1} + 2{I_2} = 4nk$$
B
$${I_1} + 2{I_2} = 2nk$$
C
$${I_1} + n{I_2} = 4{n^2}k$$
D
$${I_1} + n{I_2} = 6{n^2}k$$
3
JEE Main 2022 (Online) 28th June Morning Shift
+4
-1 Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral $$\int\limits_0^1 {[ - 8{x^2} + 6x - 1]dx}$$ is equal to :

A
$$-$$1
B
$${{ - 5} \over 4}$$
C
$${{\sqrt {17} - 13} \over 8}$$
D
$${{\sqrt {17} - 16} \over 8}$$
4
JEE Main 2022 (Online) 27th June Evening Shift
+4
-1 If m and n respectively are the number of local maximum and local minimum points of the function $$f(x) = \int\limits_0^{{x^2}} {{{{t^2} - 5t + 4} \over {2 + {e^t}}}dt}$$, then the ordered pair (m, n) is equal to

A
(3, 2)
B
(2, 3)
C
(2, 2)
D
(3, 4)
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