1
JEE Main 2023 (Online) 6th April Evening Shift
+4
-1

$$\lim _\limits{n \rightarrow \infty}\left\{\left(2^{\frac{1}{2}}-2^{\frac{1}{3}}\right)\left(2^{\frac{1}{2}}-2^{\frac{1}{5}}\right) \ldots . .\left(2^{\frac{1}{2}}-2^{\frac{1}{2 n+1}}\right)\right\}$$ is equal to

A
$$\sqrt{2}$$
B
1
C
$$\frac{1}{\sqrt{2}}$$
D
0
2
JEE Main 2023 (Online) 6th April Morning Shift
+4
-1

Let $$5 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x > 0$$. Then $$18 \int_\limits{1}^{2} f(x) d x$$ is equal to:

A
$$10 \log _{\mathrm{e}} 2+6$$
B
$$5 \log _{e} 2-3$$
C
$$10 \log _{\mathrm{e}} 2-6$$
D
$$5 \log _{\mathrm{e}} 2+3$$
3
JEE Main 2023 (Online) 1st February Evening Shift
+4
-1

The value of the integral

$$\int\limits_{ - {\pi \over 4}}^{{\pi \over 4}} {{{x + {\pi \over 4}} \over {2 - \cos 2x}}dx}$$ is :

A
$${{{\pi ^2}} \over {6\sqrt 3 }}$$
B
$${{{\pi ^2}} \over 6}$$
C
$${{{\pi ^2}} \over {3\sqrt 3 }}$$
D
$${{{\pi ^2}} \over {12\sqrt 3 }}$$
4
JEE Main 2023 (Online) 1st February Morning Shift
+4
-1

$$\mathop {\lim }\limits_{n \to \infty } \left[ {{1 \over {1 + n}} + {1 \over {2 + n}} + {1 \over {3 + n}}\, + \,...\, + \,{1 \over {2n}}} \right]$$ is equal to

A
0
B
$${\log _e}2$$
C
$${\log _e}\left( {{2 \over 3}} \right)$$
D
$${\log _e}\left( {{3 \over 2}} \right)$$
JEE Main Subjects
Physics
Mechanics
Electricity
Optics
Modern Physics
Chemistry
Physical Chemistry
Inorganic Chemistry
Organic Chemistry
Mathematics
Algebra
Trigonometry
Coordinate Geometry
Calculus
EXAM MAP
Joint Entrance Examination