1
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
Two lines $${{x - 3} \over 1} = {{y + 1} \over 3} = {{z - 6} \over { - 1}}$$ and $${{x + 5} \over 7} = {{y - 2} \over { - 6}} = {{z - 3} \over 4}$$ intersect at the point R. The reflection of R in the xy-plane has coordinates :
A
(2, 4, 7)
B
(2, $$-$$ 4, $$-$$7)
C
(2, $$-$$ 4, 7)
D
($$-$$ 2, 4, 7)
2
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
If the point (2, $$\alpha$$, $$\beta$$) lies on the plane which passes through the points (3, 4, 2) and (7, 0, 6) and is perpendicular to the plane 2x – 5y = 15, then 2$$\alpha$$ – 3$$\beta$$ is equal to
A
12
B
7
C
17
D
5
3
JEE Main 2019 (Online) 11th January Morning Slot
+4
-1
The plane containing the line $${{x - 3} \over 2} = {{y + 2} \over { - 1}} = {{z - 1} \over 3}$$ and also containing its projection on the plane 2x + 3y $$-$$ z = 5, contains which one of the following points ?
A
($$-$$ 2, 2, 2)
B
(2, 2, 0)
C
(2, 0, $$-$$ 2)
D
(0, $$-$$ 2, 2)
4
JEE Main 2019 (Online) 11th January Morning Slot
+4
-1
The direction ratios of normal to the plane through the points (0, –1, 0) and (0, 0, 1) and making an angle $${\pi \over 4}$$ with the plane y $$-$$ z + 5 = 0 are :
A
2, $$-$$1, 1
B
$$2\sqrt 3 ,1, - 1$$
C
$$\sqrt 2 ,1, - 1$$
D
$$\sqrt 2 , - \sqrt 2$$
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