1
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
Out of Syllabus
Let P be a plane passing through the points (2, 1, 0), (4, 1, 1) and (5, 0, 1) and R be any point (2, 1, 6). Then the image of R in the plane P is :
A
(4, 3, 2)
B
(6, 5, - 2)
C
(3, 4, -2)
D
(6, 5, 2)
2
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
A plane which bisects the angle between the two given planes 2x – y + 2z – 4 = 0 and x + 2y + 2z – 2 = 0, passes through the point :
A
(1, –4, 1)
B
(1, 4, –1)
C
(2, 4, 1)
D
(2, –4, 1)
3
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
The length of the perpendicular drawn from the point (2, 1, 4) to the plane containing the lines
$$\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \lambda \left( {\widehat i + 2\widehat j - \widehat k} \right)$$ and $$\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \mu \left( { - \widehat i + \widehat j - 2\widehat k} \right)$$ is :
A
$${1 \over 3}$$
B
$${1 \over {\sqrt 3 }}$$
C
3
D
$${\sqrt 3 }$$
4
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
Out of Syllabus
If the line $${{x - 2} \over 3} = {{y + 1} \over 2} = {{z - 1} \over { - 1}}$$ intersects the plane 2x + 3y – z + 13 = 0 at a point P and the plane 3x + y + 4z = 16 at a point Q, then PQ is equal to :
A
$$2\sqrt 7$$
B
14
C
$$2\sqrt {14}$$
D
$$\sqrt {14}$$
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