1
JEE Main 2019 (Online) 12th January Morning Slot
+4
-1
Out of Syllabus
The perpendicular distance from the origin to the plane containing the two lines,

$${{x + 2} \over 3} = {{y - 2} \over 5} = {{z + 5} \over 7}$$ and

$${{x - 1} \over 1} = {{y - 4} \over 4} = {{z + 4} \over 7},$$ is :
A
$$6\sqrt {11}$$
B
$${{11} \over {\sqrt 6 }}$$
C
11
D
11$$\sqrt 6$$
2
JEE Main 2019 (Online) 12th January Morning Slot
+4
-1
Out of Syllabus
A tetrahedron has vertices P(1, 2, 1), Q(2, 1, 3), R(–1, 1, 2) and O(0, 0, 0). The angle between the faces OPQ and PQR is :
A
cos$$-$$1$$\left( {{{17} \over {31}}} \right)$$
B
cos$$-$$1$$\left( {{{9} \over {35}}} \right)$$
C
cos$$-$$1$$\left( {{{19} \over {35}}} \right)$$
D
cos$$-$$1$$\left( {{7 \over {31}}} \right)$$
3
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
Out of Syllabus
Two lines $${{x - 3} \over 1} = {{y + 1} \over 3} = {{z - 6} \over { - 1}}$$ and $${{x + 5} \over 7} = {{y - 2} \over { - 6}} = {{z - 3} \over 4}$$ intersect at the point R. The reflection of R in the xy-plane has coordinates :
A
(2, 4, 7)
B
(2, $$-$$ 4, $$-$$7)
C
(2, $$-$$ 4, 7)
D
($$-$$ 2, 4, 7)
4
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
Out of Syllabus
If the point (2, $$\alpha$$, $$\beta$$) lies on the plane which passes through the points (3, 4, 2) and (7, 0, 6) and is perpendicular to the plane 2x – 5y = 15, then 2$$\alpha$$ – 3$$\beta$$ is equal to
A
12
B
7
C
17
D
5
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