The distance of the point (1, –2, 3) from

the plane x – y + z = 5 measured parallel to

the line $${x \over 2} = {y \over 3} = {z \over { - 6}}$$ is :

The plane which bisects the line joining, the points (4, –2, 3) and (2, 4, –1) at right angles also passes through the point :

The foot of the perpendicular drawn from the point (4, 2, 3) to the line joining the points (1, –2, 3) and (1, 1, 0) lies on the plane :

A plane passing through the point (3, 1, 1) contains two lines whose direction ratios are 1, –2, 2 and 2, 3, –1 respectively. If this plane also passes through the point ($$\alpha $$, –3, 5), then $$\alpha $$ is equal to: