1
JEE Main 2020 (Online) 6th September Morning Slot
+4
-1
Out of Syllabus
The shortest distance between the lines

$${{x - 1} \over 0} = {{y + 1} \over { - 1}} = {z \over 1}$$

and x + y + z + 1 = 0, 2x – y + z + 3 = 0 is :
A
1
B
$${1 \over 2}$$
C
$${1 \over {\sqrt 2 }}$$
D
$${1 \over {\sqrt 3 }}$$
2
JEE Main 2020 (Online) 5th September Evening Slot
+4
-1
Out of Syllabus
If for some $$\alpha$$ $$\in$$ R, the lines

L1 : $${{x + 1} \over 2} = {{y - 2} \over { - 1}} = {{z - 1} \over 1}$$ and

L2 : $${{x + 2} \over \alpha } = {{y + 1} \over {5 - \alpha }} = {{z + 1} \over 1}$$ are coplanar,

then the line L2 passes through the point :
A
(10, 2, 2)
B
(2, –10, –2)
C
(10, –2, –2)
D
(–2, 10, 2)
3
JEE Main 2020 (Online) 5th September Morning Slot
+4
-1
If (a, b, c) is the image of the point (1, 2, -3) in

the line $${{x + 1} \over 2} = {{y - 3} \over { - 2}} = {z \over { - 1}}$$, then a + b + c is :
A
1
B
2
C
3
D
-1
4
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
Out of Syllabus
The distance of the point (1, –2, 3) from

the plane x – y + z = 5 measured parallel to

the line $${x \over 2} = {y \over 3} = {z \over { - 6}}$$ is :
A
7
B
1
C
$${1 \over 7}$$
D
$${7 \over 5}$$
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