1
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
The shortest distance between the lines $${x \over 2} = {y \over 2} = {z \over 1}$$ and
$${{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}$$ lies in the interval :
A
[0, 1)
B
[1, 2)
C
(2,  3]
D
(3, 4]
2
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
Out of Syllabus
The distance of the point (1, − 2, 4) from the plane passing through the point (1, 2, 2) and perpendicular to the planes x − y + 2z = 3 and 2x − 2y + z + 12 = 0, is :
A
$$2\sqrt 2$$
B
2
C
$$\sqrt 2$$
D
$${1 \over {\sqrt 2 }}$$
3
JEE Main 2016 (Offline)
+4
-1
Out of Syllabus
If the line, $${{x - 3} \over 2} = {{y + 2} \over { - 1}} = {{z + 4} \over 3}\,$$ lies in the planes, $$lx+my-z=9,$$ then $${l^2} + {m^2}$$ is equal to :
A
$$5$$
B
$$2$$
C
$$26$$
D
$$18$$
4
JEE Main 2016 (Offline)
+4
-1
Out of Syllabus
The distance of the point $$(1,-5,9)$$ from the plane $$x-y+z=5$$ measured along the line $$x=y=z$$ is :
A
$${{10} \over {\sqrt 3 }}$$
B
$${20 \over 3}$$
C
$$3\sqrt {10}$$
D
$$10\sqrt {3}$$
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