JEE Main 2023 (Online) 1st February Morning Shift | 3D Geometry Question 147 | Mathematics

The shortest distance between the lines

$${{x - 5} \over 1} = {{y - 2} \over 2} = {{z - 4} \over { - 3}}$$ and

$${{x + 3} \over 1} = {{y + 5} \over 4} = {{z - 1} \over { - 5}}$$ is :

$$7\sqrt 3 $$

$$5\sqrt 3 $$

$$4\sqrt 3 $$

$$6\sqrt 3 $$

JEE Main 2023 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

Let the image of the point $$P(2,-1,3)$$ in the plane $$x+2 y-z=0$$ be $$Q$$.

Then the distance of the plane $$3 x+2 y+z+29=0$$ from the point $$Q$$ is :

$$2\sqrt{14}$$

$$\frac{22\sqrt2}{7}$$

$$\frac{24\sqrt2}{7}$$

$$3\sqrt{14}$$

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

Let the plane $\mathrm{P}: 8 x+\alpha_{1} y+\alpha_{2} z+12=0$ be parallel to

the line $\mathrm{L}: \frac{x+2}{2}=\frac{y-3}{3}=\frac{z+4}{5}$. If the intercept of $\mathrm{P}$

on the $y$-axis is 1 , then the distance between $\mathrm{P}$ and $\mathrm{L}$ is :

$\frac{6}{\sqrt{14}}$

$\sqrt{14}$

$\sqrt{\frac{2}{7}}$

$\sqrt{\frac{7}{2}}$

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

The foot of perpendicular from the origin $\mathrm{O}$ to a plane $\mathrm{P}$ which meets the co-ordinate axes at the points $\mathrm{A}, \mathrm{B}, \mathrm{C}$ is $(2, \mathrm{a}, 4), \mathrm{a} \in \mathrm{N}$. If the volume of the tetrahedron $\mathrm{OABC}$ is 144 unit$^{3}$, then which of the following points is NOT on P ?

$(3,0,4)$

$(0,6,3)$

$(0,4,4)$

$(2,2,4)$

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