1
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
If the length of the perpendicular from the point ($$\beta$$, 0, $$\beta$$) ($$\beta$$ $$\ne$$ 0) to the line,
$${x \over 1} = {{y - 1} \over 0} = {{z + 1} \over { - 1}}$$ is $$\sqrt {{3 \over 2}}$$, then $$\beta$$ is equal to :
A
2
B
1
C
-2
D
-1
2
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
Out of Syllabus
If Q(0, –1, –3) is the image of the point P in the plane 3x – y + 4z = 2 and R is the point (3, –1, –2), then the area (in sq. units) of $$\Delta$$PQR is :
A
$${{\sqrt {65} } \over 2}$$
B
$$2\sqrt {13}$$
C
$${{\sqrt {91} } \over 2}$$
D
$${{\sqrt {91} } \over 4}$$
3
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
The vertices B and C of a $$\Delta$$ABC lie on the line,

$${{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}$$ such that BC = 5 units.

Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :
A
6
B
$$5\sqrt {17}$$
C
$$\sqrt {34}$$
D
$$2\sqrt {34}$$
4
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
Out of Syllabus
Let P be the plane, which contains the line of intersection of the planes, x + y + z – 6 = 0 and 2x + 3y + z + 5 = 0 and it is perpendicular to the xy-plane. Then the distance of the point (0, 0, 256) from P is equal to :
A
205$$\sqrt5$$
B
63$$\sqrt5$$
C
11/$$\sqrt5$$
D
17/$$\sqrt5$$
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