1
JEE Main 2023 (Online) 31st January Evening Shift
+4
-1
Out of Syllabus
Let the plane $\mathrm{P}: 8 x+\alpha_{1} y+\alpha_{2} z+12=0$ be parallel to

the line $\mathrm{L}: \frac{x+2}{2}=\frac{y-3}{3}=\frac{z+4}{5}$. If the intercept of $\mathrm{P}$

on the $y$-axis is 1 , then the distance between $\mathrm{P}$ and $\mathrm{L}$ is :
A
$\frac{6}{\sqrt{14}}$
B
$\sqrt{14}$
C
$\sqrt{\frac{2}{7}}$
D
$\sqrt{\frac{7}{2}}$
2
JEE Main 2023 (Online) 31st January Evening Shift
+4
-1
Out of Syllabus
The foot of perpendicular from the origin $\mathrm{O}$ to a plane $\mathrm{P}$ which meets the co-ordinate axes at the points $\mathrm{A}, \mathrm{B}, \mathrm{C}$ is $(2, \mathrm{a}, 4), \mathrm{a} \in \mathrm{N}$. If the volume of the tetrahedron $\mathrm{OABC}$ is 144 unit$^{3}$, then which of the following points is NOT on P ?
A
$(3,0,4)$
B
$(0,6,3)$
C
$(0,4,4)$
D
$(2,2,4)$
3
JEE Main 2023 (Online) 31st January Evening Shift
+4
-1
Out of Syllabus
Let $P$ be the plane, passing through the point $(1,-1,-5)$ and perpendicular to the line joining the points $(4,1,-3)$ and $(2,4,3)$. Then the distance of $P$ from the point $(3,-2,2)$ is :
A
5
B
4
C
6
D
7
4
JEE Main 2023 (Online) 31st January Evening Shift
+4
-1
Out of Syllabus
If a point $\mathrm{P}(\alpha, \beta, \gamma)$ satisfying

$$\left( {\matrix{ \alpha & \beta & \gamma \cr } } \right)\left( {\matrix{ 2 & {10} & 8 \cr 9 & 3 & 8 \cr 8 & 4 & 8 \cr } } \right) = \left( {\matrix{ 0 & 0 & 0 \cr } } \right)$$

lies on the plane $2 x+4 y+3 z=5$, then $6 \alpha+9 \beta+7 \gamma$ is equal to :
A
$\frac{11}{5}$
B
11
C
$-1$
D
$\frac{5}{4}$
EXAM MAP
Medical
NEET
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
CBSE
Class 12