1
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
The shortest distance between the lines

$${{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}$$ and

$${{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}$$ is :
A
3
B
$${7 \over 2}\sqrt {30}$$
C
$$3\sqrt {30}$$
D
$$2\sqrt {30}$$
2
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
Out of Syllabus
Let P be a plane passing through the points (2, 1, 0), (4, 1, 1) and (5, 0, 1) and R be any point (2, 1, 6). Then the image of R in the plane P is :
A
(4, 3, 2)
B
(6, 5, - 2)
C
(3, 4, -2)
D
(6, 5, 2)
3
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
A plane which bisects the angle between the two given planes 2x – y + 2z – 4 = 0 and x + 2y + 2z – 2 = 0, passes through the point :
A
(1, –4, 1)
B
(1, 4, –1)
C
(2, 4, 1)
D
(2, –4, 1)
4
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
The length of the perpendicular drawn from the point (2, 1, 4) to the plane containing the lines
$$\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \lambda \left( {\widehat i + 2\widehat j - \widehat k} \right)$$ and $$\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \mu \left( { - \widehat i + \widehat j - 2\widehat k} \right)$$ is :
A
$${1 \over 3}$$
B
$${1 \over {\sqrt 3 }}$$
C
3
D
$${\sqrt 3 }$$
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