AIEEE 2010 | 3D Geometry Question 213 | Mathematics

AIEEE 2010

MCQ (Single Correct Answer)

-1

Statement-1: The point $$A(3, 1, 6)$$ is the mirror image of the point $$B(1, 3, 4)$$ in the plane $$x-y+z=5.$$

Statement-2: The plane $$x-y+z=5$$ bisects the line segment joining $$A(3, 1, 6)$$ and $$B(1, 3, 4).$$

Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1.

Statement - 1 is true, Statement - 2 is false.

Statement - 1 is false , Statement - 2 is true.

Statement - 1 is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - 1.

AIEEE 2010

MCQ (Single Correct Answer)

-1

A line $$AB$$ in three-dimensional space makes angles $${45^ \circ }$$ and $${120^ \circ }$$ with the positive $$x$$-axis and the positive $$y$$-axis respectively. If $$AB$$ makes an acute angle $$\theta $$ with the positive $$z$$-axis, then $$\theta $$ equals

$${45^ \circ }$$

$${60^ \circ }$$

$${75^ \circ }$$

$${30^ \circ }$$

AIEEE 2009

MCQ (Single Correct Answer)

-1

Let the line $$\,\,\,\,\,$$ $${{x - 2} \over 3} = {{y - 1} \over { - 5}} = {{z + 2} \over 2}$$ lie in the plane $$\,\,\,\,\,$$ $$x + 3y - \alpha z + \beta = 0.$$ Then $$\left( {\alpha ,\beta } \right)$$ equals

$$(-6,7)$$

$$(5,-15)$$

$$(-5,5)$$

$$(6, -17)$$

AIEEE 2008

MCQ (Single Correct Answer)

-1

The line passing through the points $$(5,1,a)$$ and $$(3, b, 1)$$ crosses the $$yz$$-plane at the point $$\left( {0,{{17} \over 2}, - {{ - 13} \over 2}} \right)$$ . Then

$$a=2,$$ $$b=8$$

$$a=4,$$ $$b=6$$

$$a=6,$$ $$b=4$$

$$a=8,$$ $$b=2$$

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