1
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
A equation of a plane parallel to the plane $$x-2y+2z-5=0$$ and at a unit distance from the origin is :
A
$$x-2y+2z-3=0$$
B
$$x-2y+2z+1=0$$
C
$$x-2y+2z-1=0$$
D
$$x-2y+2z+5=0$$
2
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
If the line $${{x - 1} \over 2} = {{y + 1} \over 3} = {{z - 1} \over 4}$$ and $${{x - 3} \over 1} = {{y - k} \over 2} = {z \over 1}$$ intersect, then $$k$$ is equal to :
A
$$-1$$
B
$${2 \over 9}$$
C
$${9 \over 2}$$
D
$$0$$
3
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
If the angle between the line $$x = {{y - 1} \over 2} = {{z - 3} \over \lambda }$$ and the plane

$$x+2y+3z=4$$ is $${\cos ^{ - 1}}\left( {\sqrt {{5 \over {14}}} } \right),$$ then $$\lambda $$ equals :
A
$${3 \over 2}$$
B
$${2 \over 5}$$
C
$${5 \over 3}$$
D
$${2 \over 3}$$
4
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Statement - 1 : The point $$A(1,0,7)$$ is the mirror image of the point

$$B(1,6,3)$$ in the line : $${x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3}$$

Statement - 2 : The line $${x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3}$$ bisects the line

segment joining $$A(1,0,7)$$ and $$B(1, 6, 3)$$
A
Statement -1 is true, Statement -2 is true; Statement -2 is not a correct explanation for Statement -1.
B
Statement -1 is true, Statement - 2 is false.
C
Statement - 1 is false , Statement -2 is true.
D
Statement -1 is true, Statement -2 is true; Statement -2 is a correct explanation for Statement -1.
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