1
JEE Main 2022 (Online) 30th June Morning Shift
+4
-1
Out of Syllabus

Let a vector $$\overrightarrow c$$ be coplanar with the vectors $$\overrightarrow a = - \widehat i + \widehat j + \widehat k$$ and $$\overrightarrow b = 2\widehat i + \widehat j - \widehat k$$. If the vector $$\overrightarrow c$$ also satisfies the conditions $$\overrightarrow c \,.\,\left[ {\left( {\overrightarrow a + \overrightarrow b } \right) \times \left( {\overrightarrow a \times \overrightarrow b } \right)} \right] = - 42$$ and $$\left( {\overrightarrow c \times \left( {\overrightarrow a - \overrightarrow b } \right)} \right)\,.\,\widehat k = 3$$, then the value of $$|\overrightarrow c {|^2}$$ is equal to :

A
24
B
29
C
35
D
42
2
JEE Main 2022 (Online) 29th June Evening Shift
+4
-1
Let A, B, C be three points whose position vectors respectively are

$$\overrightarrow a = \widehat i + 4\widehat j + 3\widehat k$$

$$\overrightarrow b = 2\widehat i + \alpha \widehat j + 4\widehat k,\,\alpha \in R$$

$$\overrightarrow c = 3\widehat i - 2\widehat j + 5\widehat k$$

If $$\alpha$$ is the smallest positive integer for which $$\overrightarrow a ,\,\overrightarrow b ,\,\overrightarrow c$$ are noncollinear, then the length of the median, in $$\Delta$$ABC, through A is :

A
$${{\sqrt {82} } \over 2}$$
B
$${{\sqrt {62} } \over 2}$$
C
$${{\sqrt {69} } \over 2}$$
D
$${{\sqrt {66} } \over 2}$$
3
JEE Main 2022 (Online) 29th June Morning Shift
+4
-1

Let $$\overrightarrow a = \alpha \widehat i + 3\widehat j - \widehat k$$, $$\overrightarrow b = 3\widehat i - \beta \widehat j + 4\widehat k$$ and $$\overrightarrow c = \widehat i + 2\widehat j - 2\widehat k$$ where $$\alpha ,\,\beta \in R$$, be three vectors. If the projection of $$\overrightarrow a$$ on $$\overrightarrow c$$ is $${{10} \over 3}$$ and $$\overrightarrow b \times \overrightarrow c = - 6\widehat i + 10\widehat j + 7\widehat k$$, then the value of $$\alpha + \beta$$ is equal to :

A
3
B
4
C
5
D
6
4
JEE Main 2022 (Online) 28th June Evening Shift
+4
-1

Let $$\overrightarrow a = \alpha \widehat i + 2\widehat j - \widehat k$$ and $$\overrightarrow b = - 2\widehat i + \alpha \widehat j + \widehat k$$, where $$\alpha \in R$$. If the area of the parallelogram whose adjacent sides are represented by the vectors $$\overrightarrow a$$ and $$\overrightarrow b$$ is $$\sqrt {15({\alpha ^2} + 4)}$$, then the value of $$2{\left| {\overrightarrow a } \right|^2} + \left( {\overrightarrow a \,.\,\overrightarrow b } \right){\left| {\overrightarrow b } \right|^2}$$ is equal to :

A
10
B
7
C
9
D
14
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