1
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
If $$C$$ is the mid point of $$AB$$ and $$P$$ is any point outside $$AB,$$ then :
A
$$\overrightarrow {PA} + \overrightarrow {PB} = 2\overrightarrow {PC} $$
B
$$\overrightarrow {PA} + \overrightarrow {PB} = \overrightarrow {PC} $$
C
$$\overrightarrow {PA} + \overrightarrow {PB} = 2\overrightarrow {PC} = \overrightarrow 0 $$
D
$$\overrightarrow {PA} + \overrightarrow {PB} = \overrightarrow {PC} = \overrightarrow 0 $$
2
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
For any vector $${\overrightarrow a }$$ , the value of $${\left( {\overrightarrow a \times \widehat i} \right)^2} + {\left( {\overrightarrow a \times \widehat j} \right)^2} + {\left( {\overrightarrow a \times \widehat k} \right)^2}$$ is equal to :
A
$$3{\overrightarrow a ^2}$$
B
$${\overrightarrow a ^2}$$
C
$$2{\overrightarrow a ^2}$$
D
$$4{\overrightarrow a ^2}$$
3
AIEEE 2004
MCQ (Single Correct Answer)
+4
-1
Let $$\overrightarrow a ,\overrightarrow b $$ and $$\overrightarrow c $$ be non-zero vectors such that $$\left( {\overrightarrow a \times \overrightarrow b } \right) \times \overrightarrow c = {1 \over 3}\left| {\overrightarrow b } \right|\left| {\overrightarrow c } \right|\overrightarrow a \,\,.$$ If $$\theta $$ is the acute angle between the vectors $${\overrightarrow b }$$ and $${\overrightarrow c },$$ then $$sin\theta $$ equals :
A
$${{2\sqrt 2 } \over 3}$$
B
$${{\sqrt 2 } \over 3}$$
C
$${2 \over 3}$$
D
$${1 \over 3}$$
4
AIEEE 2004
MCQ (Single Correct Answer)
+4
-1
Let $$\overrightarrow a ,\overrightarrow b $$ and $$\overrightarrow c $$ be three non-zero vectors such that no two of these are collinear. If the vector $$\overrightarrow a + 2\overrightarrow b $$ is collinear with $$\overrightarrow c $$ and $$\overrightarrow b + 3\overrightarrow c $$ is collinear with $$\overrightarrow a $$ ($$\lambda $$ being some non-zero scalar) then $$\overrightarrow a + 2\overrightarrow b + 6\overrightarrow c $$ equals to :
A
$\overrightarrow{0}$
B
$$\lambda \overrightarrow b $$
C
$$\lambda \overrightarrow c $$
D
$$\lambda \overrightarrow a $$

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