1
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
If $$\overrightarrow a ,\overrightarrow b ,\overrightarrow c $$ are non coplanar vectors and $$\lambda $$ is a real number then

$$\left[ {\lambda \left( {\overrightarrow a + \overrightarrow b } \right)\,\,\,\,\,\,\,\,{\lambda ^2}\overrightarrow b \,\,\,\,\,\,\,\,\lambda \overrightarrow c } \right] = \left[ {\overrightarrow a \,\,\,\,\,\,\,\,\overrightarrow b + \overrightarrow c \,\,\,\,\,\,\,\,\overrightarrow b } \right]$$ for :
A
exactly one value of $$\lambda $$
B
no value of $$\lambda $$
C
exactly three values of $$\lambda $$
D
exactly two values of $$\lambda $$
2
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
For any vector $${\overrightarrow a }$$ , the value of $${\left( {\overrightarrow a \times \widehat i} \right)^2} + {\left( {\overrightarrow a \times \widehat j} \right)^2} + {\left( {\overrightarrow a \times \widehat k} \right)^2}$$ is equal to :
A
$$3{\overrightarrow a ^2}$$
B
$${\overrightarrow a ^2}$$
C
$$2{\overrightarrow a ^2}$$
D
$$4{\overrightarrow a ^2}$$
3
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Let $$\overrightarrow a \,\, = \,\,\widehat i - \widehat k,\,\,\,\,\,\overrightarrow b \,\,\, = \,\,\,x\widehat i + \widehat j\,\,\, + \,\,\,\left( {1 - x} \right)\widehat k$$ and $$\overrightarrow c \,\, = \,\,y\widehat i + x\widehat j + \left( {1 + x - y} \right)\widehat k.$$ Then $$\left[ {\overrightarrow a ,\overrightarrow b ,\overrightarrow c } \right]$$ depends on :
A
only $$y$$
B
only $$x$$
C
both $$x$$ and $$y$$
D
neither $$x$$ nor $$y$$
4
AIEEE 2004
MCQ (Single Correct Answer)
+4
-1
Let $$\overrightarrow a ,\overrightarrow b $$ and $$\overrightarrow c $$ be three non-zero vectors such that no two of these are collinear. If the vector $$\overrightarrow a + 2\overrightarrow b $$ is collinear with $$\overrightarrow c $$ and $$\overrightarrow b + 3\overrightarrow c $$ is collinear with $$\overrightarrow a $$ ($$\lambda $$ being some non-zero scalar) then $$\overrightarrow a + 2\overrightarrow b + 6\overrightarrow c $$ equals to :
A
$\overrightarrow{0}$
B
$$\lambda \overrightarrow b $$
C
$$\lambda \overrightarrow c $$
D
$$\lambda \overrightarrow a $$
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