The direction ratios of normal to the plane through the points (0, –1, 0) and (0, 0, 1) and making an angle $${\pi \over 4}$$ with the plane y $$-$$ z + 5 = 0 are :

On which of the following lines lies the point of intersection of the line,   $${{x - 4} \over 2} = {{y - 5} \over 2} = {{z - 3} \over 1}$$  and the plane, x + y + z = 2 ?

The plane which bisects the line segment joining the points (–3, –3, 4) and (3, 7, 6) at right angles, passes through which one of the following points ?

The plane passing through the point (4, –1, 2) and parallel to the lines  $${{x + 2} \over 3} = {{y - 2} \over { - 1}} = {{z + 1} \over 2}$$  and  $${{x - 2} \over 1} = {{y - 3} \over 2} = {{z - 4} \over 3}$$ also passes through the point -