1
AIEEE 2004
MCQ (Single Correct Answer)
+4
-1
If the straight lines
$$x=1+s,y=-3$$$$ - \lambda s,$$ $$z = 1 + \lambda s$$ and $$x = {t \over 2},y = 1 + t,z = 2 - t,$$ with parameters $$s$$ and $$t$$ respectively, are co-planar, then $$\lambda $$ equals :
A
$$0$$
B
$$-1$$
C
$$ - {1 \over 2}$$
D
$$-2$$
2
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The shortest distance from the plane $$12x+4y+3z=327$$ to the sphere

$${x^2} + {y^2} + {z^2} + 4x - 2y - 6z = 155$$ is
A
$$39$$
B
$$26$$
C
$$11{4 \over {13}}$$
D
$$13$$
3
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The radius of the circle in which the sphere

$${x^2} + {y^2} + {z^2} + 2x - 2y - 4z - 19 = 0$$ is cut by the plane

$$x+2y+2z+7=0$$ is
A
$$4$$
B
$$1$$
C
$$2$$
D
$$3$$
4
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Two systems of rectangular axes have the same origin. If a plane cuts then at distances $$a,b,c$$ and $$a', b', c'$$ from the origin then
A
$${1 \over {{a^2}}} + {1 \over {{b^2}}} + {1 \over {{c^2}}} - {1 \over {a{'^2}}} - {1 \over {b{'^2}}} - {1 \over {c{'^2}}} = 0$$
B
$$\,{1 \over {{a^2}}} + {1 \over {{b^2}}} + {1 \over {{c^2}}} + {1 \over {a{'^2}}} + {1 \over {b{'^2}}} + {1 \over {c{'^2}}} = 0$$
C
$${1 \over {{a^2}}} + {1 \over {{b^2}}} - {1 \over {{c^2}}} + {1 \over {a{'^2}}} - {1 \over {b{'^2}}} - {1 \over {c{'^2}}} = 0$$
D
$${1 \over {{a^2}}} - {1 \over {{b^2}}} - {1 \over {{c^2}}} + {1 \over {a{'^2}}} - {1 \over {b{'^2}}} - {1 \over {c{'^2}}} = 0$$

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