1
JEE Main 2023 (Online) 30th January Evening Shift
+4
-1
Out of Syllabus
If a plane passes through the points $(-1, k, 0),(2, k,-1),(1,1,2)$ and is parallel to the line $\frac{x-1}{1}=\frac{2 y+1}{2}=\frac{z+1}{-1}$, then the value of $\frac{k^2+1}{(k-1)(k-2)}$ is :
A
$\frac{17}{5}$
B
$\frac{6}{13}$
C
$\frac{13}{6}$
D
$\frac{5}{17}$
2
JEE Main 2023 (Online) 30th January Morning Shift
+4
-1
Out of Syllabus

The line $$l_1$$ passes through the point (2, 6, 2) and is perpendicular to the plane $$2x+y-2z=10$$. Then the shortest distance between the line $$l_1$$ and the line $$\frac{x+1}{2}=\frac{y+4}{-3}=\frac{z}{2}$$ is :

A
9
B
7
C
$$\frac{19}{3}$$
D
$$\frac{13}{3}$$
3
JEE Main 2023 (Online) 29th January Evening Shift
+4
-1
Out of Syllabus

The plane $$2x-y+z=4$$ intersects the line segment joining the points A ($$a,-2,4)$$ and B ($$2,b,-3)$$ at the point C in the ratio 2 : 1 and the distance of the point C from the origin is $$\sqrt5$$. If $$ab < 0$$ and P is the point $$(a-b,b,2b-a)$$ then CP$$^2$$ is equal to :

A
$$\frac{17}{3}$$
B
$$\frac{97}{3}$$
C
$$\frac{16}{3}$$
D
$$\frac{73}{3}$$
4
JEE Main 2023 (Online) 29th January Evening Shift
+4
-1
Out of Syllabus

If the lines $${{x - 1} \over 1} = {{y - 2} \over 2} = {{z + 3} \over 1}$$ and $${{x - a} \over 2} = {{y + 2} \over 3} = {{z - 3} \over 1}$$ intersect at the point P, then the distance of the point P from the plane $$z = a$$ is :

A
28
B
22
C
10
D
16
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