33% OFF
ExamGOAL
MOST RELEVANT

JEE Main Ultimate Online Test Series - 2027

458 Tests
10,140 Questions
English & Hindi (हिन्दी) Languages
331 Topic Tests87 Chapter Tests30 Full Tests10 Part Tests
  • Most Relevant Questions for JEE Main 2027
  • JEE Main Predictive Percentile and Rank
  • Best Solution to Every Question
  • Very Detailed Analysis
₹999 ₹1,499
Save ₹500
Access valid till 31 May 2027
Check Out
1
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $${\Delta _1} = \left| {\matrix{ x & {\sin \theta } & {\cos \theta } \cr { - \sin \theta } & { - x} & 1 \cr {\cos \theta } & 1 & x \cr } } \right|$$ and
$${\Delta _2} = \left| {\matrix{ x & {\sin 2\theta } & {\cos 2\theta } \cr { - \sin 2\theta } & { - x} & 1 \cr {\cos 2\theta } & 1 & x \cr } } \right|$$, $$x \ne 0$$ ;

then for all $$\theta \in \left( {0,{\pi \over 2}} \right)$$ :
A
$${\Delta _1} - {\Delta _2}$$ = x (cos 2$$\theta $$ – cos 4$$\theta $$)
B
$${\Delta _1} + {\Delta _2}$$ = - 2x3
C
$${\Delta _1} + {\Delta _2}$$ = – 2(x3 + x –1)
D
$${\Delta _1} - {\Delta _2}$$ = - 2x3
2
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the system of equations 2x + 3y – z = 0, x + ky – 2z = 0 and 2x – y + z = 0 has a non-trival solution (x, y, z), then $${x \over y} + {y \over z} + {z \over x} + k$$ is equal to :-
A
-4
B
$${3 \over 4}$$
C
$${1 \over 2}$$
D
$$-{1 \over 4}$$
3
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The total number of matrices
$$A = \left( {\matrix{ 0 & {2y} & 1 \cr {2x} & y & { - 1} \cr {2x} & { - y} & 1 \cr } } \right)$$
(x, y $$ \in $$ R,x $$ \ne $$ y) for which ATA = 3I3 is :-
A
3
B
4
C
2
D
6
4
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\left[ {\matrix{ 1 & 1 \cr 0 & 1 \cr } } \right]\left[ {\matrix{ 1 & 2 \cr 0 & 1 \cr } } \right]$$$$\left[ {\matrix{ 1 & 3 \cr 0 & 1 \cr } } \right]$$....$$\left[ {\matrix{ 1 & {n - 1} \cr 0 & 1 \cr } } \right] = \left[ {\matrix{ 1 & {78} \cr 0 & 1 \cr } } \right]$$,

then the inverse of $$\left[ {\matrix{ 1 & n \cr 0 & 1 \cr } } \right]$$ is
A
$$\left[ {\matrix{ 1 & { 0} \cr {12} & 1 \cr } } \right]$$
B
$$\left[ {\matrix{ 1 & { 0} \cr {13} & 1 \cr } } \right]$$
C
$$\left[ {\matrix{ 1 & { - 13} \cr 0 & 1 \cr } } \right]$$
D
$$\left[ {\matrix{ 1 & { - 12} \cr 0 & 1 \cr } } \right]$$

JEE Main Subjects

Browse all chapters by subject