1
AIEEE 2002
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$a>0$$ and discriminant of $$\,a{x^2} + 2bx + c$$ is $$-ve$$, then
$$\left| {\matrix{ a & b & {ax + b} \cr b & c & {bx + c} \cr {ax + b} & {bx + c} & 0 \cr } } \right|$$ is equal to
A
$$+ve$$
B
$$\left( {ac - {b^2}} \right)\left( {a{x^2} + 2bx + c} \right)$$
C
$$-ve$$
D
$$0$$
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