1
JEE Main 2020 (Online) 3rd September Evening Slot
+4
-1
Let A be a 3 $$\times$$ 3 matrix such that
adj A = $$\left[ {\matrix{ 2 & { - 1} & 1 \cr { - 1} & 0 & 2 \cr 1 & { - 2} & { - 1} \cr } } \right]$$ and B = adj(adj A).

If |A| = $$\lambda$$ and |(B-1)T| = $$\mu$$ , then the ordered pair,
(|$$\lambda$$|, $$\mu$$) is equal to :
A
(3, 81)
B
$$\left( {9,{1 \over 9}} \right)$$
C
$$\left( {3,{1 \over {81}}} \right)$$
D
$$\left( {9,{1 \over {81}}} \right)$$
2
JEE Main 2020 (Online) 3rd September Morning Slot
+4
-1
If $$\Delta$$ = $$\left| {\matrix{ {x - 2} & {2x - 3} & {3x - 4} \cr {2x - 3} & {3x - 4} & {4x - 5} \cr {3x - 5} & {5x - 8} & {10x - 17} \cr } } \right|$$ =

Ax3 + Bx2 + Cx + D, then B + C is equal to :
A
-1
B
-3
C
9
D
1
3
JEE Main 2020 (Online) 2nd September Evening Slot
+4
-1
Let a, b, c $$\in$$ R be all non-zero and satisfy
a3 + b3 + c3 = 2. If the matrix

A = $$\left( {\matrix{ a & b & c \cr b & c & a \cr c & a & b \cr } } \right)$$

satisfies ATA = I, then a value of abc can be :
A
3
B
$${1 \over 3}$$
C
-$${1 \over 3}$$
D
$${2 \over 3}$$
4
JEE Main 2020 (Online) 2nd September Evening Slot
+4
-1
Let A = {X = (x, y, z)T: PX = 0 and

x2 + y2 + z2 = 1} where

$$P = \left[ {\matrix{ 1 & 2 & 1 \cr { - 2} & 3 & { - 4} \cr 1 & 9 & { - 1} \cr } } \right]$$,

then the set A :
A
is an empty set.
B
contains more than two elements.
C
contains exactly two elements.
D
is a singleton.
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