1
JEE Main 2019 (Online) 10th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The shortest distance between the point  $$\left( {{3 \over 2},0} \right)$$   and the curve y = $$\sqrt x $$, (x > 0), is -
A
$${{\sqrt 3 } \over 2}$$
B
$${5 \over 4}$$
C
$${3 \over 2}$$
D
$${{\sqrt 5 } \over 2}$$
2
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The maximum volume (in cu.m) of the right circular cone having slant height 3 m is :
A
2$$\sqrt3$$$$\pi $$
B
3$$\sqrt3$$$$\pi $$
C
6$$\pi $$
D
$${4 \over 3}\pi $$
3
JEE Main 2018 (Online) 16th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x) = 2x3 $$-$$ 9x2 + 12x + 5 in the interval [0, 3]. Then M $$-$$m is equal to :
A
5
B
9
C
4
D
1
4
JEE Main 2018 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$f\left( x \right) = {x^2} + {1 \over {{x^2}}}$$ and $$g\left( x \right) = x - {1 \over x}$$,
$$x \in R - \left\{ { - 1,0,1} \right\}$$.
If $$h\left( x \right) = {{f\left( x \right)} \over {g\left( x \right)}}$$, then the local minimum value of h(x) is
A
$$2\sqrt 2 $$
B
3
C
-3
D
$$-2\sqrt 2 $$
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