1
JEE Main 2020 (Online) 8th January Evening Slot
+4
-1
The length of the perpendicular from the origin, on the normal to the curve,
x2 + 2xy – 3y2 = 0 at the point (2,2) is
A
$$\sqrt 2$$
B
$$4\sqrt 2$$
C
2
D
$$2\sqrt 2$$
2
JEE Main 2020 (Online) 8th January Evening Slot
+4
-1
If a hyperbola passes through the point P(10, 16) and it has vertices at (± 6, 0), then the equation of the normal to it at P is
A
2x + 5y = 100
B
x + 3y = 58
C
x + 2y = 42
D
3x + 4y = 94
3
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a ponit P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at $$\left( { - {1 \over {3\sqrt 2 }},0} \right)$$ and (0, $$\beta$$), then $$\beta$$ is equal to
A
$${{\sqrt 2 } \over 3}$$
B
$${2 \over 3}$$
C
$${{2\sqrt 2 } \over 3}$$
D
$${2 \over {\sqrt 3 }}$$
4
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
The locus of a point which divides the line segment joining the point (0, –1) and a point on the parabola, x2 = 4y, internally in the ratio 1 : 2, is :
A
9x2 – 3y = 2
B
4x2 – 3y = 2
C
x2 – 3y = 2
D
9x2 – 12y = 8
JEE Main Subjects
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Mechanics
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Modern Physics
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