1
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
If the function f given by f(x) = x3 – 3(a – 2)x2 + 3ax + 7, for some a$$\in$$R is increasing in (0, 1] and decreasing in [1, 5), then a root of the equation, $${{f\left( x \right) - 14} \over {{{\left( {x - 1} \right)}^2}}} = 0\left( {x \ne 1} \right)$$ is :
A
$$-$$ 7
B
5
C
7
D
6
2
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
Out of Syllabus
The tangent to the curve y = x2 – 5x + 5, parallel to the line 2y = 4x + 1, also passes through the point :
A
$$\left\{ {{1 \over 4},{7 \over 2}} \right\}$$
B
$$\left( { - {1 \over 8},7} \right)$$
C
$$\left( {{7 \over 2},{1 \over 4}} \right)$$
D
$$\left( {{1 \over 8}, - 7} \right)$$
3
JEE Main 2019 (Online) 11th January Evening Slot
+4
-1
Let f(x) = $${x \over {\sqrt {{a^2} + {x^2}} }} - {{d - x} \over {\sqrt {{b^2} + {{\left( {d - x} \right)}^2}} }},\,\,$$ x $$\, \in$$ R, where a, b and d are non-zero real constants. Then :
A
f is an increasing function of x
B
f is neither increasing nor decreasing function of x
C
f ' is not a continuous function of x
D
f is a decreasing function of x
4
JEE Main 2019 (Online) 11th January Morning Slot
+4
-1
The maximum value of the function f(x) = 3x3 – 18x2 + 27x – 40 on the set S = $$\left\{ {x\, \in R:{x^2} + 30 \le 11x} \right\}$$ is :
A
$$-$$ 222
B
$$-$$ 122
C
$$122$$
D
222
EXAM MAP
Medical
NEET