1
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
If the tangent to the curve, y = x3 + ax – b at the point (1, –5) is perpendicular to the line, –x + y + 4 = 0, then which one of the following points lies on the curve ?
A
(2, –2)
B
(2, –1)
C
(–2, 2)
D
(–2, 1)
2
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The height of a right circular cylinder of maximum volume inscribed in a sphere of radius 3 is
A
$$\sqrt 3 $$
B
$$2\sqrt 3 $$
C
$$\sqrt 6 $$
D
$${2 \over 3} {\sqrt 3} $$
3
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is $$2y \over x^2$$. If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is :
A
x loge|y| = 2(x – 1)
B
x2 loge|y| = –2(x – 1)
C
x loge|y| = x – 1
D
x loge|y| = –2(x – 1)
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let ƒ : [0, 2] $$ \to $$ R be a twice differentiable function such that ƒ''(x) > 0, for all x $$ \in $$ (0, 2). If $$\phi $$(x) = ƒ(x) + ƒ(2 – x), then $$\phi $$ is :
A
decreasing on (0, 2)
B
decreasing on (0, 1) and increasing on (1, 2)
C
increasing on (0, 2)
D
increasing on (0, 1) and decreasing on (1, 2)

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