1
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Out of Syllabus
Let S be the set of all values of x for which the tangent to the curve
y = ƒ(x) = x3 – x2 – 2x at (x, y) is parallel to the line segment joining the points (1, ƒ(1)) and (–1, ƒ(–1)), then S is equal to :
A
$$\left\{ { {1 \over 3}, - 1} \right\}$$
B
$$\left\{ { - {1 \over 3}, 1} \right\}$$
C
$$\left\{ { - {1 \over 3}, - 1} \right\}$$
D
$$\left\{ { {1 \over 3}, 1} \right\}$$
2
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Out of Syllabus
If the tangent to the curve, y = x3 + ax – b at the point (1, –5) is perpendicular to the line, –x + y + 4 = 0, then which one of the following points lies on the curve ?
A
(2, –2)
B
(2, –1)
C
(–2, 2)
D
(–2, 1)
3
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
Out of Syllabus
Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is $$2y \over x^2$$. If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is :
A
x loge|y| = 2(x – 1)
B
x2 loge|y| = –2(x – 1)
C
x loge|y| = x – 1
D
x loge|y| = –2(x – 1)
4
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
The height of a right circular cylinder of maximum volume inscribed in a sphere of radius 3 is
A
$$\sqrt 3$$
B
$$2\sqrt 3$$
C
$$\sqrt 6$$
D
$${2 \over 3} {\sqrt 3}$$
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