1
JEE Main 2022 (Online) 26th July Morning Shift
+4
-1

If the function $$f(x) = \left\{ {\matrix{ {{{{{\log }_e}(1 - x + {x^2}) + {{\log }_e}(1 + x + {x^2})} \over {\sec x - \cos x}}} & , & {x \in \left( {{{ - \pi } \over 2},{\pi \over 2}} \right) - \{ 0\} } \cr k & , & {x = 0} \cr } } \right.$$ is continuous at x = 0, then k is equal to:

A
1
B
$$-$$1
C
e
D
0
2
JEE Main 2022 (Online) 26th July Morning Shift
+4
-1

If $$f(x) = \left\{ {\matrix{ {x + a} & , & {x \le 0} \cr {|x - 4|} & , & {x > 0} \cr } } \right.$$ and $$g(x) = \left\{ {\matrix{ {x + 1} & , & {x < 0} \cr {{{(x - 4)}^2} + b} & , & {x \ge 0} \cr } } \right.$$ are continuous on R, then $$(gof)(2) + (fog)( - 2)$$ is equal to :

A
$$-$$10
B
10
C
8
D
$$-$$8
3
JEE Main 2022 (Online) 25th July Evening Shift
+4
-1

$$\lim\limits_{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}$$ is equal to

A
14
B
7
C
14$$\sqrt2$$
D
7$$\sqrt2$$
4
JEE Main 2022 (Online) 25th July Morning Shift
+4
-1

If $$\mathop {\lim }\limits_{n \to \infty } \left( {\sqrt {{n^2} - n - 1} + n\alpha + \beta } \right) = 0$$, then $$8(\alpha+\beta)$$ is equal to :

A
4
B
$$-$$8
C
$$-$$4
D
8
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