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1
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
Let $$f:R \to R$$ be a function defined by

$$f(x) = \min \left\{ {x + 1,\left| x \right| + 1} \right\}$$, then which of the following is true?
A
$$f(x)$$ is differentiale everywhere
B
$$f(x)$$ is not differentiable at x = 0
C
$$f(x) > 1$$ for all $$x \in R$$
D
$$f(x)$$ is not differentiable at x = 1
2
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
The function $$f:R/\left\{ 0 \right\} \to R$$ given by

$$f\left( x \right) = {1 \over x} - {2 \over {{e^{2x}} - 1}}$$

can be made continuous at $$x$$ = 0 by defining $$f$$(0) as
A
0
B
1
C
2
D
$$-1$$
3
AIEEE 2006
MCQ (Single Correct Answer)
+4
-1
The set of points where $$f\left( x \right) = {x \over {1 + \left| x \right|}}$$ is differentiable is
A
$$\left( { - \infty ,0} \right) \cup \left( {0,\infty } \right)$$
B
$$\left( { - \infty ,1} \right) \cup \left( { - 1,\infty } \right)$$
C
$$\left( { - \infty ,\infty } \right)$$
D
$$\left( {0,\infty } \right)$$
4
AIEEE 2005
MCQ (Single Correct Answer)
+4
-1
If $$f$$ is a real valued differentiable function satisfying

$$\left| {f\left( x \right) - f\left( y \right)} \right|$$ $$ \le {\left( {x - y} \right)^2}$$, $$x, y$$ $$ \in R$$
and $$f(0)$$ = 0, then $$f(1)$$ equals
A
-1
B
0
C
2
D
1

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