If a vertex of a triangle is $$(1, 1)$$ and the mid points of two sides through this vertex are $$(-1, 2)$$ and $$(3, 2)$$ then the centroid of the triangle is
A
$$\left( { - 1,{7 \over 3}} \right)$$
B
$$\left( {{{ - 1} \over 3},{7 \over 3}} \right)$$
C
$$\left( { 1,{7 \over 3}} \right)$$
D
$$\left( {{{ 1} \over 3},{7 \over 3}} \right)$$
Explanation
Vertex of triangle is $$\left( {1,\,1} \right)$$ and midpoint of sides through -
this vertex is $$\left( { - 1,\,2} \right)$$ and $$\left( {3,2} \right)$$
$$ \Rightarrow $$ vertex $$B$$ and $$C$$ come out to be $$\left( { - 3,3} \right)$$ and $$\left( {5,3} \right)$$
The line parallel to the $$x$$ - axis and passing through the intersection of the lines $$ax + 2by + 3b = 0$$ and $$bx - 2ay - 3a = 0,$$ where $$(a, b)$$ $$ \ne $$ $$(0, 0)$$ is
A
below the $$x$$ - axis at a distance of $${3 \over 2}$$ from it
B
below the $$x$$ - axis at a distance of $${2 \over 3}$$ from it
C
above the $$x$$ - axis at a distance of $${3 \over 2}$$ from it
D
above the $$x$$ - axis at a distance of $${2 \over 3}$$ from it
Explanation
The line passing through the intersection of lines