The intersection of three lines x $$-$$ y = 0, x + 2y = 3 and 2x + y = 6 is a :

The image of the point (3, 5) in the line x $$-$$ y + 1 = 0, lies on :

A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of this line on the coordinate axes is $${1 \over 4}$$. Three stones A, B and C are placed at the points (1, 1), (2, 2) and (4, 4) respectively. Then, which of these stones is / are on the path of the man?

Let L denote the line in the xy-plane with x and y intercepts as 3 and 1 respectively. Then the image of the point (–1, –4) in this line is :