1
JEE Main 2022 (Online) 24th June Evening Shift
+4
-1

Let the area of the triangle with vertices A(1, $$\alpha$$), B($$\alpha$$, 0) and C(0, $$\alpha$$) be 4 sq. units. If the points ($$\alpha$$, $$-$$$$\alpha$$), ($$-$$$$\alpha$$, $$\alpha$$) and ($$\alpha$$2, $$\beta$$) are collinear, then $$\beta$$ is equal to :

A
64
B
$$-$$8
C
$$-$$64
D
512
2
JEE Main 2021 (Online) 31st August Evening Shift
+4
-1
Let A be the set of all points ($$\alpha$$, $$\beta$$) such that the area of triangle formed by the points (5, 6), (3, 2) and ($$\alpha$$, $$\beta$$) is 12 square units. Then the least possible length of a line segment joining the origin to a point in A, is :
A
$${4 \over {\sqrt 5 }}$$
B
$${16 \over {\sqrt 5 }}$$
C
$${8 \over {\sqrt 5 }}$$
D
$${12 \over {\sqrt 5 }}$$
3
JEE Main 2021 (Online) 31st August Morning Shift
+4
-1
If p and q are the lengths of the perpendiculars from the origin on the lines,

x cosec $$\alpha$$ $$-$$ y sec $$\alpha$$ = k cot 2$$\alpha$$ and

x sin$$\alpha$$ + y cos$$\alpha$$ = k sin2$$\alpha$$

respectively, then k2 is equal to :
A
4p2 + q2
B
2p2 + q2
C
p2 + 2q2
D
p2 + 4q2
4
JEE Main 2021 (Online) 27th August Morning Shift
+4
-1
Let A be a fixed point (0, 6) and B be a moving point (2t, 0). Let M be the mid-point of AB and the perpendicular bisector of AB meets the y-axis at C. The locus of the mid-point P of MC is :
A
3x2 $$-$$ 2y $$-$$ 6 = 0
B
3x2 + 2y $$-$$ 6 = 0
C
2x2 + 3y $$-$$ 9 = 0
D
2x2 $$-$$ 3y + 9 = 0
EXAM MAP
Medical
NEET