In a triangle PQR, the co-ordinates of the points P and Q are ($$-$$2, 4) and (4, $$-$$2) respectively. If the equation of the perpendicular bisector of PR is 2x $$-$$ y + 2 = 0, then the centre of the circumcircle of the $$\Delta$$PQR is :

Let A($$-$$1, 1), B(3, 4) and C(2, 0) be given three points.
A line y = mx, m > 0, intersects lines AC and BC at point P and Q respectively. Let A₁ and A₂ be the areas of $$\Delta$$ABC and $$\Delta$$PQC respectively, such that A₁ = 3A₂, then the value of m is equal to :

The intersection of three lines x $$-$$ y = 0, x + 2y = 3 and 2x + y = 6 is a :

The image of the point (3, 5) in the line x $$-$$ y + 1 = 0, lies on :