1
JEE Main 2017 (Offline)
+4
-1
Let k be an integer such that the triangle with vertices (k, – 3k), (5, k) and (–k, 2) has area 28 sq. units. Then the orthocentre of this triangle is at the point:
A
$$\left( {1,{3 \over 4}} \right)$$
B
$$\left( {1, - {3 \over 4}} \right)$$
C
$$\left( {2,{1 \over 2}} \right)$$
D
$$\left( {2, - {1 \over 2}} \right)$$
2
JEE Main 2016 (Online) 10th April Morning Slot
+4
-1
A ray of light is incident along a line which meets another line, 7x − y + 1 = 0, at the point (0, 1). The ray is then reflected from this point along the line, y + 2x = 1. Then the equation of the line of incidence of the ray of light is :
A
41x − 38y + 38 = 0
B
41x + 25y − 25 = 0
C
41x + 38y − 38 = 0
D
41x − 25y + 25 = 0
3
JEE Main 2016 (Online) 10th April Morning Slot
+4
-1
A straight line through origin O meets the lines 3y = 10 − 4x and 8x + 6y + 5 = 0 at points A and B respectively. Then O divides the segment AB in the ratio :
A
2 : 3
B
1 : 2
C
4 : 1
D
3 : 4
4
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
If a variable line drawn through the intersection of the lines $${x \over 3} + {y \over 4} = 1$$ and $${x \over 4} + {y \over 3} = 1,$$ meets the coordinate axes at A and B, (A $$\ne$$ B), then the locus of the midpoint of AB is :
A
6xy = 7(x + y)
B
4(x + y)2 − 28(x + y) + 49 = 0
C
7xy = 6(x + y)
D
14(x + y)2 − 97(x + y) + 168 = 0
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