Let A($$-$$1, 1), B(3, 4) and C(2, 0) be given three points.
A line y = mx, m > 0, intersects lines AC and BC at point P and Q respectively. Let A₁ and A₂ be the areas of $$\Delta$$ABC and $$\Delta$$PQC respectively, such that A₁ = 3A₂, then the value of m is equal to :

The intersection of three lines x $$-$$ y = 0, x + 2y = 3 and 2x + y = 6 is a :

The image of the point (3, 5) in the line x $$-$$ y + 1 = 0, lies on :

A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of this line on the coordinate axes is $${1 \over 4}$$. Three stones A, B and C are placed at the points (1, 1), (2, 2) and (4, 4) respectively. Then, which of these stones is / are on the path of the man?