Solution of the differential equation $$ydx + \left( {x + {x^2}y} \right)dy = 0$$ is

The solution of the differential equation

$$\left( {1 + {y^2}} \right) + \left( {x - {e^{{{\tan }^{ - 1}}y}}} \right){{dy} \over {dx}} = 0,$$ is :

The degree and order of the differential equation of the family of all parabolas whose axis is $$x$$-axis, are respectively.

The solution of the equation $$\,{{{d^2}y} \over {d{x^2}}} = {e^{ - 2x}}$$