JEE Main 2019 (Online) 10th January Morning Slot | Application of Derivatives Question 88 | Mathematics | JEE Main - ExamSIDE.com

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1

JEE Main 2019 (Online) 10th January Morning Slot

MCQ (Single Correct Answer)

+4

-1

If $${{dy} \over {dx}} + {3 \over {{{\cos }^2}x}}y = {1 \over {{{\cos }^2}x}},\,\,x \in \left( {{{ - \pi } \over 3},{\pi \over 3}} \right)$$ and $$y\left( {{\pi \over 4}} \right) = {4 \over 3},$$ then $$y\left( { - {\pi \over 4}} \right)$$ equals -

A

$${1 \over 3} + {e^6}$$

B

$${1 \over 3}$$

C

$${1 \over 3}$$ + e³

D

$$-$$ $${4 \over 3}$$

2

JEE Main 2019 (Online) 10th January Morning Slot

MCQ (Single Correct Answer)

+4

-1

The shortest distance between the point $$\left( {{3 \over 2},0} \right)$$ and the curve y = $$\sqrt x $$, (x > 0), is -

A

$${{\sqrt 3 } \over 2}$$

B

$${5 \over 4}$$

C

$${3 \over 2}$$

D

$${{\sqrt 5 } \over 2}$$

3

JEE Main 2018 (Online) 16th April Morning Slot

MCQ (Single Correct Answer)

+4

-1

Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x) = 2x³ $$-$$ 9x² + 12x + 5 in the interval [0, 3]. Then M $$-$$m is equal to :

A

5

B

9

C

4

D

1

4

JEE Main 2018 (Online) 15th April Morning Slot

MCQ (Single Correct Answer)

+4

-1

If a right circular cone, having maximum volume, is inscribed in a sphere of radius 3 cm, then the curved surface area (in cm²) of this cone is :

A

$$6\sqrt 2 \pi $$

B

$$6\sqrt 3 \pi $$

C

$$8\sqrt 2 \pi $$

D

$$8\sqrt 3 \pi $$

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