1
JEE Main 2016 (Online) 10th April Morning Slot
+4
-1
A ray of light is incident along a line which meets another line, 7x − y + 1 = 0, at the point (0, 1). The ray is then reflected from this point along the line, y + 2x = 1. Then the equation of the line of incidence of the ray of light is :
A
41x − 38y + 38 = 0
B
41x + 25y − 25 = 0
C
41x + 38y − 38 = 0
D
41x − 25y + 25 = 0
2
JEE Main 2016 (Online) 10th April Morning Slot
+4
-1
A straight line through origin O meets the lines 3y = 10 − 4x and 8x + 6y + 5 = 0 at points A and B respectively. Then O divides the segment AB in the ratio :
A
2 : 3
B
1 : 2
C
4 : 1
D
3 : 4
3
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
If a variable line drawn through the intersection of the lines $${x \over 3} + {y \over 4} = 1$$ and $${x \over 4} + {y \over 3} = 1,$$ meets the coordinate axes at A and B, (A $$\ne$$ B), then the locus of the midpoint of AB is :
A
6xy = 7(x + y)
B
4(x + y)2 − 28(x + y) + 49 = 0
C
7xy = 6(x + y)
D
14(x + y)2 − 97(x + y) + 168 = 0
4
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
The point (2, 1) is translated parallel to the line L : x− y = 4 by $$2\sqrt 3$$ units. If the newpoint Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is :
A
x + y = 2 $$-$$ $$\sqrt 6$$
B
x + y = 3 $$-$$ 3$$\sqrt 6$$
C
x + y = 3 $$-$$ 2$$\sqrt 6$$
D
2x + 2y = 1 $$-$$ $$\sqrt 6$$
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