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1
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $\alpha$ and $\beta$ be the roots of the equation $x^2+2 a x+(3 a+10)=0$ such that $\alpha<1<\beta$. Then the set of all possible values of $a$ is :
A
$\left(-\infty, \frac{-11}{5}\right) \cup(5, \infty)$
B
$\left(-\infty, \frac{-11}{5}\right)$
C
$(-\infty,-3)$
D
$(-\infty,-2) \cup(5, \infty)$
2
JEE Main 2026 (Online) 21st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The sum of all the roots of the equation $(x-1)^2-5|x-1|+6=0$, is :

A

3

B

1

C

4

D

5

3
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The sum of the squares of the roots of $ |x-2|^2 + |x-2| - 2 = 0 $ and the squares of the roots of $ x^2 - 2|x-3| - 5 = 0 $, is

A

24

B

26

C

36

D

30

4
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The number of real roots of the equation $x |x - 2| + 3|x - 3| + 1 = 0$ is :

A

4

B

3

C

2

D

1

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