JEE Main 2025 (Online) 2nd April Morning Shift | Quadratic Equation and Inequalities Question 8 | Mathematics

Let $\mathrm{P}_{\mathrm{n}}=\alpha^{\mathrm{n}}+\beta^{\mathrm{n}}, \mathrm{n} \in \mathrm{N}$. If $\mathrm{P}_{10}=123, \mathrm{P}_9=76, \mathrm{P}_8=47$ and $\mathrm{P}_1=1$, then the quadratic equation having roots $\frac{1}{\alpha}$ and $\frac{1}{\beta}$ is :

$x^2+x-1=0$

$x^2-x+1=0$

$x^2+x+1=0$

$x^2-x-1=0$

JEE Main 2025 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

If the set of all $a \in \mathbf{R}$, for which the equation $2 x^2+(a-5) x+15=3 a$ has no real root, is the interval ( $\alpha, \beta$ ), and $X=|x \in Z ; \alpha < x < \beta|$, then $\sum\limits_{x \in X} x^2$ is equal to:

2139

2119

2109

2129

JEE Main 2025 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

The number of solutions of the equation

$ \left( \frac{9}{x} - \frac{9}{\sqrt{x}} + 2 \right) \left( \frac{2}{x} - \frac{7}{\sqrt{x}} + 3 \right) = 0 $ is :

JEE Main 2025 (Online) 28th January Evening Shift

MCQ (Single Correct Answer)

-1

Let $f: \mathbf{R}-\{0\} \rightarrow(-\infty, 1)$ be a polynomial of degree 2 , satisfying $f(x) f\left(\frac{1}{x}\right)=f(x)+f\left(\frac{1}{x}\right)$. If $f(\mathrm{~K})=-2 \mathrm{~K}$, then the sum of squares of all possible values of K is :