1
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Let $$\lambda \ne 0$$ be in R. If $$\alpha $$ and $$\beta $$ are the roots of the
equation, x2 - x + 2$$\lambda $$ = 0 and $$\alpha $$ and $$\gamma $$ are the roots of
the equation, $$3{x^2} - 10x + 27\lambda = 0$$, then $${{\beta \gamma } \over \lambda }$$ is equal to:
equation, x2 - x + 2$$\lambda $$ = 0 and $$\alpha $$ and $$\gamma $$ are the roots of
the equation, $$3{x^2} - 10x + 27\lambda = 0$$, then $${{\beta \gamma } \over \lambda }$$ is equal to:
2
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Let $$\alpha $$ and $$\beta $$ be the roots of x2 - 3x + p=0 and $$\gamma $$ and $$\delta $$ be the roots of x2 - 6x + q = 0. If $$\alpha, \beta, \gamma, \delta $$
form a geometric progression.Then ratio (2q + p) : (2q - p) is:
3
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Let [t] denote the greatest integer $$ \le $$ t. Then the equation in x,
[x]2 + 2[x+2] - 7 = 0 has :
[x]2 + 2[x+2] - 7 = 0 has :
4
JEE Main 2020 (Online) 3rd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
The set of all real values of $$\lambda $$ for which the
quadratic equations,
($$\lambda $$2 + 1)x2 – 4$$\lambda $$x + 2 = 0 always have exactly one root in the interval (0, 1) is :
($$\lambda $$2 + 1)x2 – 4$$\lambda $$x + 2 = 0 always have exactly one root in the interval (0, 1) is :
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