The set of all values of K > $$-$$1, for which the equation $${(3{x^2} + 4x + 3)^2} - (k + 1)(3{x^2} + 4x + 3)(3{x^2} + 4x + 2) + k{(3{x^2} + 4x + 2)^2} = 0$$ has real roots, is :
The number of real solutions of the equation, x2 $$-$$ |x| $$-$$ 12 = 0 is :
A
2
B
3
C
1
D
4
Explanation
|x|2 $$-$$ |x| $$-$$ 12 = 0
$$ \Rightarrow $$ (|x| + 3)(|x| $$-$$ 4) = 0
$$ \Rightarrow $$ |x| = 4
$$\Rightarrow$$ x = $$\pm$$2
4
JEE Main 2021 (Online) 27th July Evening Shift
MCQ (Single Correct Answer)
Let $$\alpha = \mathop {\max }\limits_{x \in R} \{ {8^{2\sin 3x}}{.4^{4\cos 3x}}\} $$ and $$\beta = \mathop {\min }\limits_{x \in R} \{ {8^{2\sin 3x}}{.4^{4\cos 3x}}\} $$. If $$8{x^2} + bx + c = 0$$ is a quadratic equation whose roots are $$\alpha$$1/5 and $$\beta$$1/5, then the value of c $$-$$ b is equal to :