1
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The number of real roots of the equation
5 + |2x – 1| = 2x (2x – 2) is
A
2
B
1
C
3
D
4
2
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
All the pairs (x, y) that satisfy the inequality
$${2^{\sqrt {{{\sin }^2}x - 2\sin x + 5} }}.{1 \over {{4^{{{\sin }^2}y}}}} \le 1$$
also satisfy the equation
A
sin x = |sin y|
B
sin x = 2sin y
C
2 sin x = sin y
D
2 |sin x | = 3 sin y
3
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$\alpha $$ and $$\beta $$ are the roots of the quadratic equation,
x2 + x sin $$\theta $$ - 2 sin $$\theta $$ = 0, $$\theta \in \left( {0,{\pi \over 2}} \right)$$, then
$${{{\alpha ^{12}} + {\beta ^{12}}} \over {\left( {{\alpha ^{ - 12}} + {\beta ^{ - 12}}} \right).{{\left( {\alpha - \beta } \right)}^{24}}}}$$ is equal to :
A
$${{{2^{12}}} \over {{{\left( {\sin \theta - 8} \right)}^6}}}$$
B
$${{{2^6}} \over {{{\left( {\sin \theta + 4} \right)}^{12}}}}$$
C
$${{{2^{12}}} \over {{{\left( {\sin \theta + 8} \right)}^{12}}}}$$
D
$${{{2^{12}}} \over {{{\left( {\sin \theta - 4} \right)}^{12}}}}$$
4
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If m is chosen in the quadratic equation

(m2 + 1) x2 – 3x + (m2 + 1)2 = 0

such that the sum of its roots is greatest, then the absolute difference of the cubes of its roots is :-
A
$$4\sqrt 3 $$
B
$$8\sqrt 3 $$
C
$$8\sqrt 5 $$
D
$$10\sqrt 5 $$
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