1
JEE Main 2020 (Online) 6th September Morning Slot
+4
-1
If $$\alpha$$ and $$\beta$$ be two roots of the equation
x2 – 64x + 256 = 0. Then the value of
$${\left( {{{{\alpha ^3}} \over {{\beta ^5}}}} \right)^{1/8}} + {\left( {{{{\beta ^3}} \over {{\alpha ^5}}}} \right)^{1/8}}$$ is :
A
1
B
3
C
2
D
4
2
JEE Main 2020 (Online) 5th September Evening Slot
+4
-1
If $$\alpha$$ and $$\beta$$ are the roots of the equation,
7x2 – 3x – 2 = 0, then the value of
$${\alpha \over {1 - {\alpha ^2}}} + {\beta \over {1 - {\beta ^2}}}$$ is equal to :
A
$${1 \over {24}}$$
B
$${{27} \over {32}}$$
C
$${{27} \over {16}}$$
D
$${3 \over 8}$$
3
JEE Main 2020 (Online) 5th September Morning Slot
+4
-1
The product of the roots of the
equation 9x2 - 18|x| + 5 = 0 is :
A
$${{5} \over {9}}$$
B
$${{5} \over {27}}$$
C
$${{25} \over {81}}$$
D
$${{25} \over {9}}$$
4
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
Let $$\lambda \ne 0$$ be in R. If $$\alpha$$ and $$\beta$$ are the roots of the
equation, x2 - x + 2$$\lambda$$ = 0 and $$\alpha$$ and $$\gamma$$ are the roots of
the equation, $$3{x^2} - 10x + 27\lambda = 0$$, then $${{\beta \gamma } \over \lambda }$$ is equal to:
A
36
B
9
C
27
D
18
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